0=2ab+b^2-(3ab+1)-5

Solution for 0=2ab+b^2-(3ab+1)-5 equation:

Simplifying
0 = 2ab + b2 + -1(3ab + 1) + -5

Reorder the terms:
0 = 2ab + b2 + -1(1 + 3ab) + -5
0 = 2ab + b2 + (1 * -1 + 3ab * -1) + -5
0 = 2ab + b2 + (-1 + -3ab) + -5

Reorder the terms:
0 = -1 + -5 + 2ab + -3ab + b2

Combine like terms: -1 + -5 = -6
0 = -6 + 2ab + -3ab + b2

Combine like terms: 2ab + -3ab = -1ab
0 = -6 + -1ab + b2

Solving
0 = -6 + -1ab + b2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'ab' to each side of the equation.
0 + ab = -6 + -1ab + ab + b2
Remove the zero:
ab = -6 + -1ab + ab + b2

Combine like terms: -1ab + ab = 0
ab = -6 + 0 + b2
ab = -6 + b2

Divide each side by 'b'.
a = -6b-1 + b

Simplifying
a = -6b-1 + b